(1/7)^x=2401

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Solution for (1/7)^x=2401 equation: 



(1/7)^x=2401

We move all terms to the left:

(1/7)^x-(2401)=0



Domain of the equation: 7)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7)^x-2401=0

We multiply all the terms by the denominator


(+1-2401*7)^x=0

We add all the numbers together, and all the variables

(-16806)^x=0

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